android - 需要帮助将进程从 Java(android) 转换为 IOS Swift

Question

背景:我在 Android 应用程序中有一个进程调整图像大小，使用位图中 30% 的 JPEG 压缩，并返回一个字节数组，我在其中转换为 base64Encoded 字符串。如果可能，我需要将此类功能移植到 IOS Swift。我正在经历网络上用于图像处理的大量方法的信息过载，我需要更多指导。这是我的安卓代码:

Bitmap bmp = null;
        Bitmap scaledBitmap = null;
        ByteArrayOutputStream baos = null;

        try
        {
            bmp = BitmapFactory.decodeByteArray(data, 0, data.length);

            //if the bitmap is smaller than 1600 wide, scale it up while preserving aspect ratio
            if(bmp.getWidth() < 1600) {
                int originalHeight = bmp.getHeight();
                int originalWidth = bmp.getWidth();

                scaledBitmap = Bitmap.createScaledBitmap(bmp, 1600,
                        originalHeight*1600/originalWidth, true);

                bmp = scaledBitmap;
                scaledBitmap = null;
            }

            baos = new ByteArrayOutputStream();
            bmp.compress(Bitmap.CompressFormat.JPEG, 30, baos); // 30% compression
            image = baos.toByteArray();
        }
        //catch stuff after this

到目前为止，这是我的 IOS Swift 代码:

func imagePickerController(picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [NSObject : AnyObject]) {
    picker.dismissViewControllerAnimated(true, completion: nil)

    let image = info[UIImagePickerControllerOriginalImage] as? UIImage

    self.imgCheckFront.image = info[UIImagePickerControllerOriginalImage] as? UIImage

    let imageData = UIImageJPEGRepresentation(info[UIImagePickerControllerOriginalImage] as? UIImage, 30.0)

    let base64String = imageData.base64EncodedStringWithOptions(.allZeros)

    }

}

我认为这与我的 Android 流程有很大不同。我在 IOS 代码中创建的结果 base64String 的大小太大了。

Answer 1

抱歉，这是一个愚蠢的错误。这个:

let imageData = UIImageJPEGRepresentation(info[UIImagePickerControllerOriginalImage] as? UIImage, 30.0)

需要是这样的:

let imageData = UIImageJPEGRepresentation(info[UIImagePickerControllerOriginalImage] as? UIImage, 0.3)