javascript - 如何使用js提取ajax调用的响应？

Question

我的函数有一个 ajax 调用

js部分

_this.ajaxPost(appUrl + "reports/appointment/save", post_str, function(response) {
  var res = eval("(" + response + ")");
  if (!res.error) {
    var data = res.msg;
  } else {
    if (res.status == "error") {
      _this.showPopMsg("error", 'Error when updating db ', res.msg);
    }
  }

}, function(response) {
  alert(response);
  var res = eval("(" + response + ")");
  _this.showPopMsg("error", 'Updating DB', res.msg);
});

php部分

echo json_encode(array("error"=> false, "status"=>"success", "msg"=>$conditions['reg']->result()));

它返回一个响应，例如，

{"error":false,"status":"success","msg":[{"name":"dreamhunter","mob_num":"9876543210","email":"afl@thnfgd"}]}

我正在尝试使用js提取msg部分，msg部分包含一个像

这样的数组

[{"name":"dream hunter","mob_num":"9876543210","email":"afl@thnfgd"}]

这里的 name、mob-num 和 email 是键，我正在尝试提取它们的值

我已经尝试过

var res = eval("(" + response + ")");
var data = res.msg;
alert(data[name]);//which is the first key

这不起作用。我怎样才能提取这个？

Answer 1

假设您有以下响应:

var x = '{"error":false,"status":"success","msg":[{"name":"dreamhunter","mob_num":"9876543210","email":"afl@thnfgd"}]}'

使用JSON.Parse您可以提取对象:

var y = JSON.parse(x);

现在你有了一个像这样的对象:

{
    error:false,
    msg: [{
        email: "afl@thnfgd"
        mob_num: "9876543210"
        name: "dreamhunter"
    }],
    status:"success"
}

要访问属性，例如第一条消息的电子邮件，您可以执行以下操作:

console.log(y.msg[0].email);

var x = '{"error":false,"status":"success","msg":[{"name":"dreamhunter","mob_num":"9876543210","email":"afl@thnfgd"}]}'
var y = JSON.parse(x);

console.log('msg[0].email: ', y.msg[0].email);