Javascript - 如何编写递归函数来构建像自动换行这样的字符串数组？

Question

我需要逐行构建一个字符串数组。它就像自动换行一样。

我将输入如下文本:

    var inputString = 'There are many variations of passages of Lorem Ipsum available, but the majority have suffered alteration';

我需要数组中的每一行最多包含 38 个字符。我不想在中间分割任何单词，因此如果 38 个字符位于单词中间，则返回到最近的空格字符。

期望的输出:

    var output = [
        'There are many variations of passages',
        'of Lorem Ipsum available, but the',
        'majority have suffered alteration'
    ];

输出不正确:

'There are many variations of passages '
'of Lorem Ipsum available, but the majo'
'rity have suffered alteration.'

我尝试用空格字符分割输入文本，最终得到以下结果:

var splitInput = [
'There',
'are',
'many'
...
] 


  function conc(arguments){
        if (arguments.length === 0) 
            return "";
        else 
            return arguments.shift() + conc(arguments);
}

我不知道如何检查参数总数是否为 38 个或更多，如果是则回溯。

Answer 1

你可以使用 string.prototype.match() 来做到这一点

    var inputString = 'There are many variations of passages of Lorem Ipsum available, but the majority have suffered alteration';


let result = inputString.match(/\b.{1,38}\b/g);

console.log(result);

由于正则表达式不重叠，您将得到所需的结果