ios - 如何在触摸 UIAlertView 之外的任何地方时关闭它？

Question

我需要在用户触摸其边界之外的任何地方时关闭 AlertView。

我知道你要打电话

alert.dismissViewControllerAnimated(true, completion: nil)

要关闭 AlertView，但只有当用户触摸除了作为 View 一部分的两个按钮之一之外的任何其他地方时，我该如何做到这一点？

这是我根据史蒂夫的建议得到的代码:

presentViewController(alert, animated: true, completion: nil)
    //Add gesture recognizer for alert ViewController when adding an event
    let tapGesture = UITapGestureRecognizer(target: self, action: "alertClose:")
    view.addGestureRecognizer(tapGesture)
    //dismiss the alert if the user click anywhere except the buttons
    func alertClose(gesture: UITapGestureRecognizer) {
        alert.dismissViewControllerAnimated(true, completion: nil)
    }

Answer 1

当您呈现警报时，使用这样的完成处理程序调用它:

self.presentViewController(alert, animated: true, completion:{
        alert.view.superview?.userInteractionEnabled = true
        alert.view.superview?.addGestureRecognizer(UITapGestureRecognizer(target: self, action: #selector(self.alertClose(_:))))
})

注意: Pre Swift 2.2 替换

#selector(self.alertClose(_:))

与

Selector("alertClose")

然后创建您的警报关闭函数:

func alertClose(gesture: UITapGestureRecognizer) {
    self.dismissViewControllerAnimated(true, completion: nil)
}

我在 iPhone 6 上用 swift 2.2 测试过