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javascript - 如何从一组数组中获取所有组合

转载 作者:行者123 更新时间:2023-11-28 12:38:27 25 4
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我有例如这些数组:

a1 = ["1", "2", "3"];
a2 = ["a", "b"];
a3 = ["q", "w", "e"];

result = ["1aq", "1aw", "1ae", "1bq", "1bw", ... "3be"];

如何在没有嵌套循环的情况下获得这个(例如也使用 jquery)?谢谢

最佳答案

我不明白嵌套循环有什么问题,但这是一个通用的解决方案:

var a = [a1, a2, a3];

var result = [""]; // start with the empty string,
for (var i=0; i<a.length; i++) { // and repeatedly
var ai = a[i],
l = ai.length;
result = $.map(result, function(r) { // make result a new array of
var ns = []; // new combinations of
for (var j=0; j<l; j++) // each of the letters in ai
ns[j] = r + ai[j]; // and the old results
return ns;
}); // using the odds of jQuery.map with returned arrays
}
return result;

关于javascript - 如何从一组数组中获取所有组合,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14663145/

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