Javascript:如何在字符串对象中的两个对象之间添加逗号但不添加最后一个对象

Question

我有字符串对象，但存储在来自另一个类的变量传递中。如何在两个对象之间添加逗号但不添加最后一个对象。下面是我的代码。

{
        "id":"57e4d12e53a5a",
        "body":"asdas",
        "published":"Fri, 
        23 Sep 2016 06:52:30 +0000",
        "type":"chat-message",
        "actor":
            {
            "displayName":"beau",
            "objectType":"person",
            "image":
                {
                "url":"http://www.gravatar.com/avatar/205e460b479e2e5b48aec07710c08d50?s=80&d=mm&r=g",
                "width":48,"height":48
                }
            }
    }
    {
        "id":"57e4d51165d97",
        "body":"jackiechanSADAS",
        "published":"Fri, 23 Sep 2016 07:09:05 +0000",
        "type":"chat-message",
        "actor":
            {
                "displayName":"beau",
                "objectType":"person",
                "image":
                    {
                        "url":"http://www.gravatar.com/avatar/205e460b479e2e5b48aec07710c08d50?s=80&d=mm&r=g",
                        "width":48,
                        "height":48
                    }
            }
    }
    {
        "id":"asas",
        "body":"peterting",
        "published":"Fri, 23 Sep 2016 07:09:05 +0000",
        "type":"chat-message",
        "actor":
            {
                "displayName":"beau",
                "objectType":"person",
                "image":
                    {
                        "url":"http://www.gravatar.com/avatar/205e460b479e2e5b48aec07710c08d50?s=80&d=mm&r=g",
                        "width":48,
                        "height":48
                    }
            }
    }

如何使用编程在对象之间添加逗号“，”而不是最后一个对象，因为我将整个内容存储为字符串并且没有“，”我无法将其解析为对象。

Answer 1

您可以使用正则表达式来实现此目的:

JSON.parse('[' + string.replace(/}\s*{/g, '},{') + ']');