javascript - 从 Java 脚本中的数组列表中排除 ID 列表

Question

我有两个数组，其中一个包含我想要从员工数组中删除的 ID 列表。

在 Java 脚本中执行此操作的最佳方法是什么？我可以使用任何 ES6 语法

{
  "excludeIDArray": [
    1,
    3,
    4
  ]
}



{
  "employee": [
    {
      "id": "1",
      "name": "joe"
    },
    {
      "id": "2",
      "name": "john"
    },
    {
      "id": "3",
      "name": "mike"
    },
    {
      "id": "4",
      "name": "alex"
    },
    {
      "id": "5",
      "name": "sean"
    }
  ]
}

我希望输出是一个看起来像这样的数组

{
  "employee": [
    {
      "id": "2",
      "name": "john"
    },
    {
      "id": "5",
      "name": "sean"
    }
  ]
}

Answer 1

只需使用 Array.prototype.filter、Array.prototype.indexOf 和 parseInt(用于将字符串 ID 转换为数字)。

const exc = {"excludeIDArray":[1,3,4]}
const inObj = {"employee":[{"id":"1","name":"joe"},{"id":"2","name":"john"},{"id":"3","name":"mike"},{"id":"4","name":"alex"},{"id":"5","name":"sean"}]}

const outObj = { 
  employee: inObj.employee.filter(e => exc.excludeIDArray.indexOf(parseInt(e.id, 10)) === -1)
}

console.log(outObj);

<小时/>

您还可以使用Array.prototype.includes (如果可用)而不是 Array.prototype.indexOf 因为它肯定更具可读性

e => !exc.excludeIDArray.includes(parseInt(e.id, 10))

<小时/>

另一个选项是将排除数组转换为 Set这将带来更好的 (O(1)) 性能

const exc = {"excludeIDArray":[1,3,4]}
const inObj = {"employee":[{"id":"1","name":"joe"},{"id":"2","name":"john"},{"id":"3","name":"mike"},{"id":"4","name":"alex"},{"id":"5","name":"sean"}]}

const exclude = new Set(exc.excludeIDArray)
const outObj = {
  employee: inObj.employee.filter(e => !exclude.has(parseInt(e.id, 10)))
}
console.info(outObj)