javascript - 循环遍历对象数组，如果属性匹配，则对该对象进行切片 - Javascript

Question

这个问题已经有答案了:

How to filter object array based on attributes? (21 个回答)

已关闭 5 年前。

我有对象数组，我正在尝试循环该数组，如果找到匹配项，我想对该对象进行切片..

var object = [
  {
    "Name": 'Kshitij',
    "LastName": 'Rangari',
    "CountryBorn": 'India',
    "CountryStay": 'USA'
  },

  {
    "Name": 'Pratik',
    "LastName": 'Rangari',
    "CountryBorn": 'India',
    "CountryStay": 'Canada'
  },

  {
    "Name": 'Pratibha',
    "LastName": 'Rangari',
    "CountryBorn": 'India',
    "CountryStay": 'India'
  },

  {
    "Name": 'Ankita',
    "LastName": 'Raut',
    "CountryBorn": 'India',
    "CountryStay": 'Australia'
  },

  {
    "Name": 'Wayne',
    "LastName": 'Rooney',
    "CountryBorn": 'UK',
    "CountryStay": 'UK'
  }

]

console.log(object);

object.forEach(function(x){
  if (x.Name==='Kshitij'){

  }
})

object.map (obj =>{

  obj.AllFirstName = obj['Name'];
  console.log(obj['AllFirstName']);

})

console.log('------------------------------')

console.log(object); 

我想循环遍历对象并想查找是否 Name === 'Kshitij'和Name ==='Pratik' ，我想从数组中删除这些对象。

我该怎么做？

Answer 1

您可以使用返回一个过滤数组，该数组过滤掉数组中对象的给定键的所有给定值。

const without = (key, values) => object => !values.includes(object[key]);

var array = [{ Name: 'Kshitij', LastName: 'Rangari', CountryBorn: 'India', CountryStay: 'USA' }, { Name: 'Pratik', LastName: 'Rangari', CountryBorn: 'India', CountryStay: 'Canada' }, { Name: 'Pratibha', LastName: 'Rangari', CountryBorn: 'India', CountryStay: 'India' }, { Name: 'Ankita', LastName: 'Raut', CountryBorn: 'India', CountryStay: 'Australia' }, { Name: 'Wayne', LastName: 'Rooney', CountryBorn: 'UK', CountryStay: 'UK' }];

console.log(array.filter(without('Name', ['Kshitij', 'Pratik'])));

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