Swift 可选绑定(bind)，检查多种类型

Question

我的类(class)有一个模型，它可能是两个不同类(class)的实例。现在我检查模型是否是我需要的类:

 guard let unwrappedModel = store.state.navigationState.getRouteSpecificState(store.state.navigationState.route) as myClassOne? else {
                assertionFailure("Wrong model for RetailSalesVC")
                return
            }

现在我想检查模型是一级还是二级。这有可能实现吗？

现在我结束了这个(但没有可选绑定(bind)):

   guard (((store.state.navigationState.getRouteSpecificState(store.state.navigationState.route) as MyClassOne?) != nil)) ||
            (((store.state.navigationState.getRouteSpecificState(store.state.navigationState.route) as MyClassTwo?) != nil)) else {
                assertionFailure("Wrong model for \(self)")
                return
        }

Answer 1

如果你想运行它，这里有一个例子:

class ModelOne {}
class ModelTwo {}

let testObjects : [Any] = [ModelOne.init(), ModelTwo.init(), NSCoder.init()]
for obj in  testObjects {
    if  (obj is ModelOne || obj is ModelTwo) {
        print("\(obj) passes")
    }else{
        print("\(obj) fails")
    }
}

应该给出以下输出:

main.ModelOne passes
main.ModelTwo passes 
<NSCoder: 0x7f93a0c02b40> fails