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JavaScript 总是返回 true

转载 作者:行者123 更新时间:2023-11-28 12:08:41 25 4
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我将此脚本添加到 jsp 文件中。

即使对于失败的情况(例如不匹配表达式和所有内容),此函数也始终返回 true。

为什么会出现这样的情况?怎么解决这个问题?

<script type="text/javascript">
function validate()
{
document.getElementById("user").innerHTML="";
document.getElementById("pass").innerHTML="";
document.getElementById("mail").innerHTML="";
document.getElementById("number").innerHTML="";

var expression = /^[a-zA-Z_.0-9]+$/;
var mailExp = /^[\w\-\.\+]+\@[a-zA-Z0-9\.\-]+\.[a-zA-z0-9]{2,4}+$/;
var numberExp = /^[0-9]+$/;
if(!document.getElementById('username').value.match(expression))
{
document.getElementById('username').focus();
document.getElementById("user").innerHTML=" Enter valid user name";
return false;
}
if(document.getElementById('password').value.length == 0)
{
document.getElementById('password').focus();
document.getElementById("pass").innerHTML = "Fill Password field";
document.getElementById("pass").style.visibility = "visible";
return false;
}
if(document.getElementById('cnfpassword').value.length == 0)
{
document.getElementById('cnfpassword').focus();
document.getElementById("pass").innerHTML = "Fill confirm Password field";
document.getElementById("pass").style.visibility = "visible";
return false;
}
if(document.getElementById('password').value != document.getElementById('cnfpassword').value)
{
document.getElementById('password').focus();
document.getElementById("pass").innerHTML = "Password and confirm password Not match";
document.getElementById("pass").style.visibility = "visible";
return false;
}
if(!document.getElementById('emailid').value.match(expression))
{
document.getElementById('emailid').focus();
document.getElementById("mail").innerHTML=" Enter valid E-mailID";
document.getElementById("mail").style.visibility = "visible";
return false;
}
if(!document.getElementById('number').value.match(numberExp))
{
document.getElementById('number').focus();
document.getElementById("number").innerHTML=" Enter only numbers";
document.getElementById("number").style.visibility = "visible";
return false;
}
else
{
return true;
}
}

最佳答案

除了重构建议之外,最简单的方法是使用 Firebug 并调试出错的地方。这将为您省去很多麻烦

关于JavaScript 总是返回 true,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6621631/

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