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ios - 无法将类型 'Swift.Array>' () 的值转换为 'Swift.Dictionary' ()

转载 作者:行者123 更新时间:2023-11-28 11:57:05 28 4
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这是我的 JSON,当我读取 ord 和 uniq 数据时出现错误

let response2 : [String: Any]  = ["Response":["status":"SUCCESS","error_code":"0","message":"SUCCESS","Array":[
["ord":"50","uniq":"5a66c2348",
"name":"SHREE","no":"UP11AT0","loc":"Hathin","lat":"23.33","lon":"87.09","date":"30-01-2018","time":"12:35:33","dis_dt":"00-00-0000","dis_tm":"00:00:00"],
["ord":"50","uniq":"5a66c2348",
"name":"SHREE","no":"UP11AT0","loc":"Hathin","lat":"23.33","lon":"87.09","date":"30-01-2018","time":"12:35:33","dis_dt":"00-00-0000","dis_tm":"00:00:00"],
["ord":"50","uniq":"5a66c2348",
"name":"SHREE","no":"UP11AT0","loc":"Hathin","lat":"23.33","lon":"87.09","date":"30-01-2018","time":"12:35:33","dis_dt":"00-00-0000","dis_tm":"00:00:00"]
]],"count":"35"]

我的代码是

let status = "\((response2["Response"]! as! [String: Any])["status"]!)"
print(status)

if status == "SUCCESS" {
let count = ((response2["Response"]! as! [String: Any])["Array"] as AnyObject).count!
print(count)
let ar = (response2["Response"]! as! [String: Any])["Array"]!
print(ar)

var ord_id: [Any] = []
for i in 0..<count {
ord_id.append((response2["Response"]! as! [String: Any])["Array"]! [0] as! [String:Any])// Here I'm getting Type 'Any' has no subscript members and
}

} else {
print("Show alert")
}

当这样写时,我得到错误:Type 'Any' has no subscript members

let ar = (response2["Response"]! as! [String: Any])["Array"]! [0] as! [String: Any]          

当我这样写时错误:无法将类型“Swift.Array>”(0x10bf341f0)的值转换为“Swift.Dictionary”(0x10bf340d0)。/p>

let ar = (response2["Response"]! as! [String: Any])["Array"]! as! [String: Any]

我无法理解确切的问题是什么以及如何解决它。

最佳答案

要计算你需要做的...

if let res = response2["Response"] as? [String: Any], let arr = res["Array"] as? [[String: Any]] {
print("array count = \(arr.count)")
} else {
print("Array not found !!")
}

要从“响应”键获取数组...

var ord_id: [Any] = []

if let res = response2["Response"] as? [String: Any] {
if let arr = res["Array"] as? [Any], arr.count > 0 {
print(arr)
ord_id = arr
}
}

编辑:

要获取“old”和“uniq”键值,您需要遍历数组并获取所需的对象。

var ordId_arr = [String]()
var uniq_arr = [String]()

for obj in ord_id {

print(obj)

if let dict = obj as? [String: Any] {
//print(dict["ord"] as! String)
//print(dict["uniq"] as! String)
//print(dict["name"] as! String)
//you can get other values in same way

if let ord = dict["ord"] as? String {
ordId_arr.append(ord)
}

if let uniq = dict["uniq"] as? String {
uniq_arr.append(uniq)
}
}

}

print("\(ordId_arr)")
print("\(uniq_arr)")

关于ios - 无法将类型 'Swift.Array<Swift.Dictionary<Swift.String, Swift.String>>' () 的值转换为 'Swift.Dictionary<Swift.String, Any>' (),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50771627/

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