ios - Swinject - 如何从一个解析器解析同一个 Controller 两次？

Question

import Swinject

class GenericsAssembly: Assembly {
    func assemble(container: Container) {
        container.register(TabBarController.self) { resolver in
            let split1 = resolver.resolve(SplitViewController.self)!
            let split2 = resolver.resolve(SplitViewController.self)!
            split1.tabBarItem = UITabBarItem(title: "1", image: UIImage(named: "icon-notepad"), selectedImage: nil)
            split2.tabBarItem = UITabBarItem(title: "2", image: UIImage(named: "icon-chat"), selectedImage: nil)
            let controller = TabBarController(view: resolver.resolve(TabBarView.self)!)
            controller.viewControllers = [
                tasksSplitViewController,
                threadsSplitViewController
            ]
            return controller
        }
        container.register(SplitViewController.self) { _ in
            return SplitViewController()
        }
        container.register(TabBarView.self) { _ in
            return TabBarView()
        }
    }
}

而且...底部只有一个TabBarItem。为什么？

如果我这样使用它:

let split1 = SplitViewController()
let split2 = SplitViewController()

那么一切都很好。;) 在我的实现中，Swinject 有什么问题？

Answer 1

你可以尝试使用这个:

container.register(SplitViewController.self, name: "second") { _ in
    return SplitViewController()
}

let split2 = container.resolve(SplitViewController.self, name: "second")

以其他方式容器将返回已经解析的 Controller