ios - 我想在与 api 数据对应的标签中将可用时间显示为粗体和不可用时间(罢工)

Question

对于一天的 api 数据(所有日期和星期日关闭的不同时间)和日期，获取进入时间和离开时间，从中将标签更改为粗体可用时间并在不可用时间上敲击。

进入时间前所有时间不可用，离开后所有时间不可用，午餐时间也不可用

如何将 api 数据的条件写入标签更改(粗体/删除)

API 响应:

 Optional(<__NSSingleObjectArrayI 0x600003873050>(
 {
  day = Saturday;
  dArray = "<null>";
  enteringTime = "09.00 am";
  entryTime = "<null>";
  exitTime = "<null>";
  id = 13;
  leavingTime = "06.00 pm";
  lunchtimeFrom = "13:00";
  lunchtimeTo = "14:00";
 }

代码片段:

let attributeString: NSMutableAttributedString = NSMutableAttributedString(string: "08:05 AM") 

attributeString.addAttribute(NSAttributedString.Key.strikethroughStyle, value: 2, range: NSMakeRange(0, attributeString.length)) 

time805Lbl.attributedText = attributeString

Answer 1

在您的 viewController 中定义日期格式 -

let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "hh:mm a"
dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)

现在，添加一个检查可用时间的方法

func checkAvailableTime(currentTime: String) -> NSMutableAttributedString {

    let attributeString: NSMutableAttributedString = NSMutableAttributedString(string: currentTime)

    var time = "\(times["lunchtimeFrom"]!)"
    let lunchStartTime = dateFormatter.date(from: time)

    time = "\(times["lunchtimeTo"]!)"
    let lunchEndTime = dateFormatter.date(from: time)


    let personCheckTime = dateFormatter.date(from: currentTime)


    if  (lunchStartTime!.compare(personCheckTime!) == .orderedAscending) && (lunchEndTime!.compare(personCheckTime!) == .orderedDescending){

        attributeString.addAttribute(NSAttributedString.Key.strikethroughStyle, value: 2, range: NSMakeRange(0, attributeString.length))
    }

    return attributeString
}

是时候调用该方法了 -

time805Lbl.attributedText = checkAvailableTime(currentTime: time805Lbl.text!)

times 是您的响应时间。我希望你得到如下回应 -

let times = [
    "day":"Saturday",
    "dArray":"<null>",
    "enteringTime":"09:00 AM",
    "entryTime":"<null>",
    "exitTime":"<null>",
    "id": 13,
    "leavingTime":"06:00 PM",
    "lunchtimeFrom":"1:00 PM",
    "lunchtimeTo":"2:00 PM"
    ] as [String : Any]

如果您还有任何问题，请告诉我。