ios - 表达式类型 '@lvalue String?' 在没有更多上下文的情况下不明确

Question

无中生有我得到了这个错误表达式类型'@lvalue String?'在我的代码中没有更多上下文是模棱两可的:

    if textView.text != "" && takenImage != nil && userLocation.text != "" {
        checkInternet()
        // Create and save a new job
        let newJob = Job(text: textView.text, jobImage: takenImage!, addedByUser: (userLabel?.text)!(-> ERROR), userImage: UserImage, location: userLocation.text, passMap: takenLocation, userID: userID, postID: key)
        newJob.save()
    } 

我试图用其他问题的答案来解决它，但我没有让它工作......

工作类别:

var text: String = ""
var location: String = ""
var map: String?
var passMap: String?
var addedByUser: String?
var userImage: UIImage?
var jobImage: UIImage?
var downloadURL: String?
var userDownloadURL: String?
var numberOfLikes = 0
var numberOfDislikes = 0
let ref: DatabaseReference!
var userID: String?
var postID: String?


init(text: String? = nil, jobImage: UIImage? = nil, addedByUser: String? = nil, userImage: UIImage? = nil, location: String? = nil, passMap: String? = nil, userID: String? = nil, postID: String? = nil, data: [String : Any]) {
    self.text = text!
    self.jobImage = jobImage
    self.addedByUser = addedByUser
    self.userImage = userImage
    self.location = location!
    self.passMap = passMap
    self.userID = userID
    self.postID = postID
    ref = Database.database().reference().child("jobs").childByAutoId()
}

Answer 1

在上面的代码中，

1. 直接使用 userLabel?.text 而不展开任何内容。 addedByUser 是 String? 类型。

2. 您正在为 userImage 参数使用 UserImage 类型。请改用 UIImage 实例或 nil。

3. 您还没有在代码中添加data 参数。

这是代码，

let newJob = Job(text: textView.text, jobImage: takenImage, addedByUser: userLabel?.text, userImage: nil, location: userLocation.text, passMap: takenLocation, userID: userID, postID: key, data: [:])

避免不必要地强制展开 optionals。它可能会导致运行时异常。