ios - Swift Firebase 将 UID 键与 UID 字符串数组匹配

Question

我想弄清楚如何将我的“数据”数组中的 Firebase UID 字符串与我从 firebase 调用中提取的键相匹配。我需要将“数据”数组中的字符串与“键”相匹配，然后我就可以按我想要的方式操作数据。

 var data = [String]()

 Database.database().reference().child("Businesses").observe(.value, with: { snapshot in
        guard let allUsers = snapshot.children.allObjects as? [DataSnapshot] else {return}
        print(allUsers)
        print("Printing all users right here")
        for user in allUsers {
            let key = user.key
            print(key)
            print("Printing the keys right here come and check this out in the print")

        }
    })

我的尝试，答案不在此代码中

 Database.database().reference().child("Businesses").observeSingleEvent(of: .value, with: { snapshot in
            self.businessUID = snapshot.value as? NSDictionary
            if let dict = snapshot.value as? NSDictionary {
                for item in dict {
                    let json = JSON(item.value)
                    let businessUid = json["uid"].stringValue
                    for uid in self.data {
                        if uid == businessUid {
                            Database.database().reference().child("Businesses").observe(.value, with: { snapshot in
                                guard let allUsers = snapshot.children.allObjects as? [DataSnapshot] else {return}
                                print(allUsers)
                                print("Printing all users right here")
                                for user in allUsers {
                                    let key = user.key
                                    print(key)
                                    print("Printing the keys right here come and check this out in the print")
                                    if key == uid {
                                        print(key)
                                        print("printing the matching keys here")
                                    }

                                }
                            })
                            print(uid)
                            print("Printing the uids here")

                            Database.database().reference().child("Businesses").child(self.businessessuids).observe(.value, with: { snapshot in
                                print(snapshot)
                                print(self.businessessuids)

                            })

                        }
                    }
                }
            }

    })

更新:找到匹配值但无法保存

Database.database().reference().child("Businesses").observe(.value, with: { snapshot in
        if snapshot.exists() {
            for snapChild in snapshot.children {
                if let user: Dictionary? = (snapChild as! DataSnapshot).value as? [String : AnyObject] {
                    let businessUID = user!["uid"] as! String
                    for uid in self.data {
                        if uid == businessUID {
                            let key = uid.jsonKey
                            print(key)
                            //print(uid)
                            print("checking uid's")
                            //let name = user.childSnapshot(forPath: "name").value as! String
                            let Ref = Database.database().reference().child("testing")
                            let saveUID = Ref.child(key).child("their_name")
                        }
                    }
                }
            }
        }

    })

Answer 1

我对快照做了一些修改。虽然我还没有验证，因为我没有像你一样设置任何 Firebase 数据库。

Database.database().reference().child("Businesses").observe(.value, with: { snapshot in

        if snapshot.exists() {

            for snapChild in snapshot.children {

                if let user: Dictionary? = (snapChild as! DataSnapshot).value as? [String : AnyObject] {

                    debugPrint("User uid: ", user!["uid"] as! String)
                }
            }
        }

    })

用上面的代码片段替换你的电话，如果你仍然有任何问题，请告诉我。

注意:您还可以将所有用户结构即兴创作到模型中以便更好地使用。