ios - 一次可以选择两次的自定义选择器

Question

如何在 iOS 中设计此屏幕。

一次可以选择两次，如果可以的话是什么方法？

Answer 1

谢谢@Sudhin Davis，这是个好主意，但最后我决定继续，不对 UI 进行任何更改。我从@Harry 的评论中找到了解决方案。这是我所做的修复工作

let maxV = 25000
override func awakeFromNib() {
    self.pickerVIew.delegate = self
    self.pickerVIew.dataSource = self
    self.pickerViewLoaded(0, component: 0)
    self.pickerViewLoaded(0, component: 1)
    self.pickerViewLoaded(0, component: 3)
    self.pickerViewLoaded(0, component: 4)

}
func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int
{
    return 6
}
func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int
{
    if(component == 2 || component == 5)
    {
        return 2
    }
    else
    {
        return maxV
    }
}
func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String!
{
    if(component == 0 || component == 3)
    {
        return String(format: "%02d", (row%12)+1)
    }
    else if(component == 1 || component == 4)
    {

        return String(format: "%02d", (row%12)*5)
    }
    else
    {
        return row == 0 ? "AM" : "PM"
    }
}
func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
    self.pickerViewLoaded(row,component: component)
}
func pickerViewLoaded(row:Int,component:Int)
{
    var base12 = (maxV/2)-(maxV/2)%12;
    self.pickerVIew.selectRow(row%12+base12, inComponent: component, animated: false)
}