css - sass 编译错误说 $color : null is not a color even though i declared color

Question

我是 sass 的新手，我写了一些 sass 代码，但它没有编译。

 $classes : primary secondary success warning danger;
    $colors : (primary:#007bff,secondary : #6c757d,success: #28a745,warning: #ffc107,dangaer: #dc3545);
    @each $class in $classes{
      .btn-#{$class}{
        $currentColor: map-get($colors,#{$class});
        background:linear-gradient(to right,$currentColor,lighten($currentColor,10%));
      }
    }

错误是:

$color: null is not a color.
stdin 14:55  root stylesheet on line 14 at column 55

但是当我用变量替换 linear-gradient 时它工作正常即

$classes : primary secondary success warning danger;
$colors : (primary:#007bff,secondary : #6c757d,success: #28a745,warning: #ffc107,dangaer: #dc3545);

    @each $class in $classes{
      .btn-#{$class}{
        $currentColor: map-get($colors,#{$class});
        background:$currentColor;
        //background:linear-gradient(to right,$currentColor,lighten($currentColor,10%));
      }
    }

这是编译成功的代码。

linear-gradient() 函数中 $currentColor 变量的作用和作用是什么

Answer 1

确实，将变量从 map-get 传递到其他 sass 函数确实有些问题。

但是你可以稍微修改你的代码，它会起作用:

$classes: primary secondary success warning danger;
$colors: (
    primary: ( normal: #007bff, light: lighten(#007bff,10%) ),
    secondary: ( normal: #6c757d, light: lighten(#6c757d,10%) ),
    success: ( normal: #28a745, light: lighten(#28a745,10%) ),
    warning: ( normal: #ffc107, light: lighten(#ffc107,10%) ),
    danger: ( normal: #dc3545, light: lighten(#dc3545,10%) )
);
@each $class in $classes{
  .btn-#{$class}{
    $currentColor: map-get(map-get($colors,#{$class}), normal);
    $currentColorLighten: map-get(map-get($colors,#{$class}), light);

    background: linear-gradient(to right, $currentColor, $currentColorLighten);
  }
}

你为每个类定义了两种颜色(普通版和亮版)，然后通过双映射获取来使用它。