php - Zend Ajax无法删除

Question

我有一个名为 state 的表，其中包含 state_id、state_name 列。目前我可以添加新状态并编辑它们，但无法删除状态。我的代码可能有什么问题？

{title:"Actions",template:'<a class="left" onclick="javascript:openEditStatePopup(this);">Edit</a>' + 
    '<a class="right" onclick="javascript:deleteState(this);">Delete</a>'
    ,width:120,sortable:false}

此代码段是 View 代码，当我单击链接时，它会执行以下 JavaScript:

function deleteState(element)
{
    var countryDetail = {};
    var GriddataItem = $("#state_grid").data("kendoGrid").dataItem($(element).closest("tr"));
    countryDetail.state_id =GriddataItem.state_id;
    countryDetail.state_name = GriddataItem.state_name;
    // alert(countryDetail.state_id);
    $.ajax({
        url:"<?= $this->baseUrl('admin/state/delete')?>",
        data: {state_id :  countryDetail.state_id},
        dataType: "json",
        type: "POST",
        success: function(){
            alert('success');
        },
        failure:function(){
            alert('not working');
        }
    });
}

当我在 $.ajax 调用之前 echo alert(countryDetail.state_id) 时，我可以获得正确的州 ID。

我的删除 Controller 是:

public function deleteAction()
{

    $state = $this->_request->_getPost('state_id');
    $stateMapper = new Application_Model_Mapper_StateMapper();
    $stateMapper->delete($state);
}

用于删除的模型映射器是:

public function delete(Application_Model_State $state)
{
    $data = $state->toArray();
    $adapter = $this->getDbTable()->getAdapter()->delete(array('state_id=?'=>$data['state_id']));
}

Answer 1

您好，您需要编写deleteAction如下

public function deleteAction()
{


    $state = $this->_getParam('state_id');
    $stateMapper = new Application_Model_Mapper_StateMapper();
    $stateId = $stateMapper->delete($state);
    $this->_helper->json(array('success'=>1));
}