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php - 将 JSON 解析数组转换为 CSV

转载 作者:行者123 更新时间:2023-11-28 09:32:17 24 4
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首先我看到了 The Other Threads,我认为它们都没有使用 PHP 或 javascript。

在编码并添加斜杠以转义 JSON 非法字符后,我得到了这个数组:

"#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12"  "#Tahrir","2012-Oct-19" "#Tahrir","2012-Oct-19" "#Tahrir","2012-Oct-19"

想要将其更改为 CSV 或找到一种方法将其与此示例中的图表一起使用:http://bl.ocks.org/3883245#data.tsv

提前谢谢。

最佳答案

要将 json 数据转换为 CSV,请尝试使用此 http://jsfiddle.net/sturtevant/vUnF9/ (不是我的代码)

function JSON2CSV(objArray) {
var array = typeof objArray != 'object' ? JSON.parse(objArray) : objArray;

var str = '';
var line = '';

if ($("#labels").is(':checked')) {
var head = array[0];
if ($("#quote").is(':checked')) {
for (var index in array[0]) {
var value = index + "";
line += '"' + value.replace(/"/g, '""') + '",';
}
} else {
for (var index in array[0]) {
line += index + ',';
}
}

line = line.slice(0, -1);
str += line + '\r\n';
}

for (var i = 0; i < array.length; i++) {
var line = '';

if ($("#quote").is(':checked')) {
for (var index in array[i]) {
var value = array[i][index] + "";
line += '"' + value.replace(/"/g, '""') + '",';
}
} else {
for (var index in array[i]) {
line += array[i][index] + ',';
}
}

line = line.slice(0, -1);
str += line + '\r\n';
}
return str;
}

关于php - 将 JSON 解析数组转换为 CSV,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13590553/

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