swift - 阿拉伯文本剥离器/解析器

Question

我是编程新手。我做了一个函数，可以删除阿拉伯语文本输入中的元音。我的问题是我是否使用了该任务的最佳循环，或者是否有更好、更简洁的方式来编写它？

如果能改进代码就好了。谢谢。

// It seems to work now. I solved it.
// What do you think? :) Happy that I managed to solve it.
// Programming is fun!!! :D
var arabic:String = "الْعَرَبِيَّةُ لُغَةٌ جَمِيلَةٌ"

func txtStripper(arabic: String) -> String {
    var strippedTxt = ""
    for character in arabic {
        if character != "َ" && character != "ِ" && character != "ّ" && character != "ْ" && character != "ُ" && character != "ٌ" && character != "ً" && character != "ٍ" {
            strippedTxt += toString(print(character))
        }
    }
    return strippedTxt
}
txtStripper(arabic)

Answer 1

首先，您可以使用 contains 函数清理 if 语句。

func txtStripper(arabic: String) -> String {
    var strippedTxt = ""
    let vowels : Character[] = ["َ", "ِ", "ّ", "ْ", "ُ", "ٌ", "ً", "ٍ"]

    for character in arabic {
        if !contains (vowels, character) {
            strippedTxt += toString(character)
        }
    }
    return strippedTxt
}

接下来，如果您对闭包感到满意，您可以用更简洁的方式重写整个函数，如下所示:

func txtStripperWithClosures(arabic:String) -> String {
    let vowels : Character[] = ["َ", "ِ", "ّ", "ْ", "ُ", "ٌ", "ً", "ٍ"]
    return Array(arabic).filter({!contains(vowels, $0)}).reduce("",+)
}

它的工作原理如下:

• Array(arabic) 将 String 转换为 Character[]
• filter({!contains(vowels, $0)}) 从数组中移除元音字符
• reduce("",+) 将字符列表连接回一个字符串