ios - 获取快速发布变量时出错

Question

我已经在 swift ios 中创建了一个 HTTP POST 请求。当我在 php 文件中获取一个 post 变量时，它显示为空白，我没有得到变量值。在我的 swift 代码下面，看一下。

var dataString = "name=john&type=student"

var request : NSMutableURLRequest = NSMutableURLRequest()

request.URL = NSURL(string: "http://www.example.com/example.php")

var postString = (dataString as NSString).dataUsingEncoding(NSUTF8StringEncoding)

request.HTTPMethod = "POST"

request.setValue("application/json", forHTTPHeaderField: "Content-Type")

request.HTTPBody = postString

var connection = NSURLConnection(request: request, delegate: self, startImmediately: false)

func connection(didReceiveResponse: NSURLConnection!, didReceiveResponse response: NSURLResponse!) {
    //New request so we need to clear the data object
    println(response)
}

PHP代码:

<?php
echo $_POST['name'];
?>

任何人都可以建议我应该如何获取变量值。谢谢

Answer 1

您应该使用 application/x-www-form-urlencoded 的 Content-Type 而不是 application/json