javascript - 用下划线或其他东西组合 2 个 MongoDB 集合对象？

Question

我正在查询所有评论和commentLikes。本质上，我在 View 中循环浏览评论集合，但我需要将 commentLikes 与 comments 关联起来。现在，commentLikes 对 comments._id 的引用为 commentLikes.comment_id。

我正在考虑为此使用下划线，因为看起来有一些不错的实用函数，但我会使用哪些？我最终使用了 _.where 但不确定这是否是适合这项工作的工具。

这是最好的方法吗？

var comments = 
[ { submission_id: '513d3702b99f8b1ca5000026',
    comment: 'asdfnasdfoiasdfiosdaf',
    user_id: '1',
    _id: '5157e79c562277e457000011',
    deleted: false,
    created: 'Sun Mar 31 2013 00:37:00 GMT-0700 (PDT)',
    parent_id: null },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment: 'asdfioasdfoiasdjiofasdijofjiasodf',
    user_id: '1',
    _id: '5157e799562277e457000010',
    deleted: false,
    created: 'Sun Mar 31 2013 00:36:57 GMT-0700 (PDT)',
    parent_id: null },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment: 'sdafijsadjiofasoijfjaiosdfjioasdfjiosdaf',
    user_id: '1',
    _id: '5157e797562277e45700000f',
    deleted: false,
    created: 'Sun Mar 31 2013 00:36:55 GMT-0700 (PDT)',
    parent_id: null },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment: 'asdfjiadsfojidfsjoaifdaijofdasijods',
    user_id: '1',
    _id: '5157e794562277e45700000e',
    deleted: false,
    created: 'Sun Mar 31 2013 00:36:52 GMT-0700 (PDT)',
    parent_id: null },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment: 'asdfiasdfijoasdfoijas',
    user_id: '1',
    _id: '5157e40227bf651157000280',
    deleted: false,
    created: 'Sun Mar 31 2013 00:21:38 GMT-0700 (PDT)',
    parent_id: null } ];

var commentLikes =
    [ { submission_id: '513d3702b99f8b1ca5000026',
    comment_id: '5157e40227bf651157000280',
    user_id: 1,
    _id: '5157e40527bf651157000286',
    created: 'Sun Mar 31 2013 00:21:41 GMT-0700 (PDT)' },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment_id: '5157e40227bf651157000280',
    user_id: 1,
    _id: '5157e40b27bf65115700028e',
    created: 'Sun Mar 31 2013 00:21:47 GMT-0700 (PDT)' },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment_id: '5157e797562277e45700000f',
    user_id: 1,
    _id: '5157e7cc9c1fe3ed57000001',
    created: 'Sun Mar 31 2013 00:37:48 GMT-0700 (PDT)' },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment_id: '5157e799562277e457000010',
    user_id: 1,
    _id: '5157e7cd9c1fe3ed57000002',
    created: 'Sun Mar 31 2013 00:37:49 GMT-0700 (PDT)' },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment_id: '5157e79c562277e457000011',
    user_id: 1,
    _id: '5157e7ce9c1fe3ed57000003',
    created: 'Sun Mar 31 2013 00:37:50 GMT-0700 (PDT)' },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment_id: '5157e79c562277e457000011',
    user_id: 1,
    _id: '5157e7d19c1fe3ed57000004',
    created: 'Sun Mar 31 2013 00:37:53 GMT-0700 (PDT)' },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment_id: '5157e79c562277e457000011',
    user_id: 1,
    _id: '5157e7d29c1fe3ed57000005',
    created: 'Sun Mar 31 2013 00:37:54 GMT-0700 (PDT)' },
  { submission_id: '513d3702b99f8b1ca5000026',
    comment_id: '5157e79c562277e457000011',
    user_id: 1,
    _id: '5157e7d29c1fe3ed57000006',
    created: 'Sun Mar 31 2013 00:37:54 GMT-0700 (PDT)' } ];

var newCommentObj = comments;

_.map(newCommentObj, function(key) {
    // get commentLikes for each comment
    var commentId = key._id,
        likes = _.where(commentLikes, {comment_id : commentId});

});

如果没有，我应该怎么做？对多个 Mongoose 集合执行此操作的正确方法是什么？我有传统的 MySQL 背景，所以我已经习惯了没有关联。

Answer 1

您可以使用下划线的groupBy和map here is来做到这一点工作示例。

您还可以使用mapReduce在“mongodb”合并您的集合 look here了解更多详情。