php - 有效的 JSON 不适用于 jQuery.parseJSON()

Question

我正在将 JSON 字符串保存到文件中并尝试将其读回。由于某种原因，它不会读回它。 jsonlint.com 告诉我这是一个有效的 JSON。

这是 JSON 字符串:

{"userdef":{"vlan10":{"dfault":{"down":{"rate":"876","ceil":"876"},"up":{"rate":"876","ceil":"876"}},"upsell":{"down":{"rate":"876","ceil":"876"},"up":{"rate":"876","ceil":"76"}}},"br0":{"dfault":{"down":{"rate":"798","ceil":"987"},"up":{"rate":"987","ceil":"987"}},"upsell":{"down":{"rate":"98","ceil":"987"},"up":{"rate":"987","ceil":"89"}}},"br1":{"dfault":{"down":{"rate":"3","ceil":"654"},"up":{"rate":"654","ceil":"63"}},"upsell":{"down":{"rate":"65","ceil":"4"},"up":{"rate":"646","ceil":"5"}}},"eth3":{"dfault":{"down":{"rate":"65","ceil":"7876"},"up":{"rate":"7657","ceil":"5"}},"upsell":{"down":{"rate":"7865","ceil":"7"},"up":{"rate":"7","ceil":"5"}}}}}

这是 javascript/php 代码:

<?
if (file_exists('/tmp/qosconfig.conf'))
{
?>
var config = jQuery.parseJSON('<?=file_get_contents("/tmp/qosconfig.conf");?>');    
<?
}
?>

Answer 1

这是一种相当奇怪的方法。如果您在 PHP 中有可用的 JSON 字符串，则可以将其作为对象文字输出到 javascript，从而节省解析步骤。

<?
if (file_exists('/tmp/qosconfig.conf')) {
    $json = file_get_contents('/tmp/qosconfig.conf');
?>
var config = <?php echo $json; ?>;    
<?
}
?>