swift - Swift Core Data 中的一对多关系

Question

我正在构建一个日记应用程序，您可以在其中创建一个 FocusArea 对象，然后该对象包含 30 个日记条目对象。

所以我在我的数据模型中创建了一对多关系。

然后我实现了两个 NSManagedObject 类:

@objc(焦点区域)类 FocusArea: NSManagedObject {

@NSManaged var focusName: String
@NSManaged var focusStart: NSDate
@NSManaged var focusEnd: NSDate
@NSManaged var completeFlag: Bool
//@NSManaged var entries: NSSet

var entries: NSMutableOrderedSet {
    return self.mutableOrderedSetValueForKey("entries")
}  

@objc(条目)类条目:NSManagedObject {

 @NSManaged var entryJournal: String
 @NSManaged var entryDate: NSDate
 @NSManaged var completeFlag: Bool
 @NSManaged var entryStatus: Bool
 @NSManaged var focus: FocusArea

我可以毫无问题地添加一个 FocusArea，但是当我尝试创建 30 个 Entry 对象并存储在 FocusArea.entries 中时，一切都会崩溃。

将多个 Entry 对象添加到 FocusArea 对象的正确方法是什么？

我离这里很远吗？

@IBAction func saveFocusArea(sender: AnyObject) {

    if txtFocusName.text != nil {

        let appDel: AppDelegate = UIApplication.sharedApplication().delegate as! AppDelegate
        let context: NSManagedObjectContext = appDel.managedObjectContext!

        //create new focus area
        let entFocus = NSEntityDescription.entityForName("FocusArea", inManagedObjectContext: context)
        let newFocus = FocusArea(entity:entFocus!, insertIntoManagedObjectContext: context)

        newFocus.focusName = txtFocusName.text!
        newFocus.focusStart = NSDate()
        newFocus.focusEnd = NSDate().dateByAddingTimeInterval(60*60*24*30)
        newFocus.completeFlag = false

        //initialize 30 new entries into core data
        let entEntry = NSEntityDescription.entityForName("Entry", inManagedObjectContext: context)

        for var i = 0; i < 30; i++ {

            let newEntry = Entry(entity:entEntry!, insertIntoManagedObjectContext: context)

            let c = Double(i)
            newEntry.entryDate = NSDate().dateByAddingTimeInterval(60*60*24*c)
            newEntry.entryJournal = ""
            newEntry.entryStatus = false
            newEntry.completeFlag = false

            //THIS IS THE PROBLEM AREA
            newFocus.entries.append(newEntry)
        }
        do {
            try context.save()
        } catch {
            print("There's a problem!")
        }
    }
} 

Answer 1

我想通了。我所要做的就是:

newEntry.focus = 新焦点。

所以不是设置父到子的关系，而是设置从子到父的关系。