ios - 尝试在 Parse 中查询对象

Question

query.findObjectsInBackgroundWithBlock { (objects:[AnyObject]?, error:NSError?) -> Void in

        if error == nil {
            if let objects = objects as? [PFObject] {
                for object in objects {
                    print("woot")
                }
            }

        } else {
            // Log details of the failure
            print("Error: \(error) \(error!.userInfo)")
        }
        dispatch_async(dispatch_get_main_queue()){
            //reload the table view

            query.cachePolicy = PFCachePolicy.NetworkElseCache
        }

    }

出于某种原因，该行:

query.findObjectsInBackgroundWithBlock { (objects:[AnyObject]?, error:NSError?) -> Void in

给我错误:

Cannot convert value of type '([AnyObject]?, NSError?) -> void to expected argument type 'PFQueryArrayResultBlock?'

我不知道如何修复错误。

谢谢!

Answer 1

结果 block 应该如下所示:

query.findObjectsInBackgroundWithBlock {
    (objects: [PFObject]?, error: NSError?) -> Void in

    if error == nil {
        if let objects = objects as? [PFObject] {
            for object in objects {
                print("woot")
            }
        }

    } else {
        // Log details of the failure
        print("Error: \(error) \(error!.userInfo)")
    }
    dispatch_async(dispatch_get_main_queue()){
        //reload the table view

        query.cachePolicy = PFCachePolicy.NetworkElseCache
    }
}

参见 Parse docs关于查询。