javascript - Socket.io 发射不起作用，但广播正常

Question

我试图向单个客户端发出通知，但发出似乎根本没有触发，而broadcast.emit 工作正常。但问题是广播会通知所有客户端，即使我提供了 socket.id。

有人知道我做错了什么吗？

var app = express( );
var querystring = require('querystring');
var server  = http.createServer(app);
var io = require('socket.io').listen(server);
var clients = {};

io.sockets.on('connection', function( socket ) {
    socket.on( 'subscribe', function( userID ) {
        clients[userID] = socket.id;
    });

    socket.on( 'notifyMsg', function( data ) {
        var obj = JSON.parse( data );
        for( var i=0; i<obj.info.notifyUserIDs.length; i++ ) {
            var to = clients[obj.info.notifyUserIDs[i]];
            if( to ) {
                // Doesn't work
                io.sockets.socket(to).emit( 'notification', data );

                // Works
                //io.sockets.socket(to).broadcast.emit( 'notification', data );
            }
        }
    });
});

Answer 1

您对将套接字本身存储在客户端哈希中并像这样使用它有何看法？

var app = express( );
var querystring = require('querystring');
var server  = http.createServer(app);
var io = require('socket.io').listen(server);
var clients = {};

io.sockets.on('connection', function( socket ) {
    socket.on( 'subscribe', function( userID ) {
        clients[userID] = socket;
    });

    socket.on( 'notifyMsg', function( data ) {
        var obj = JSON.parse( data );
        for( var i=0; i<obj.info.notifyUserIDs.length; i++ ) {
            var to = clients[obj.info.notifyUserIDs[i]];
            if( to ) {
                to.emit( 'notification', data );
            }
        }
    });
});