ios - 3DTouch UIPreviewAction : performseguewithidentifier not working

Question

我在我的 iOS Swift 应用程序中实现了一些 UIPreviewActions。但是，这些操作会执行 segue 事务，而这些事务将被忽略。我怎样才能做到这一点？

有一个类似的问题，但是在 Objective-C 中:UIPreviewAction to Mail From Peek

override func previewActionItems() -> [UIPreviewActionItem] {
    let performSegueAction = UIPreviewAction(title: "Go To View", style: .Default) { (action, viewController) -> Void in
    self.performSegueWithIdentifier("segueID", sender: self)
    }
    return [performSegueAction]
}

Answer 1

抱歉回复晚了，但最近我自己遇到了这个问题，所以张贴答案以防其他人发现它有用...

在调用 UIPreviewAction 中的处理程序时， View Controller 已经从层次结构中删除，因此执行 segues 没有任何效果。相反，你应该这样做:

class PreviewViewController: UIViewController {

var performAction: (() -> Void)?

override func previewActionItems() -> [UIPreviewActionItem] {
    let performSegueAction = UIPreviewAction(title: "Go To View", style: .Default) { (action, viewController) -> Void in
        self.performAction?()
    }
    return [performSegueAction]
}

并且在父 Controller 中(您从中启动预览):

class ParentViewController: UIViewController {

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if let vc = segue.destination as? PreviewViewController {
        vc.handleAction = {
            self.performSegueWithIdentifier("segueID", sender: self)
        }
    }
    inject(toController: segue.destination)
}