c++ - 将代码转换为数组并显示

Question

我怎样才能把它变成一个数组？我需要一个板来显示空白，当用户输入时，另一个函数会用 X 或 O 填充它。目前的板子作品我想把它做成一个数组[3][3]并显示数组的内容。

void showboard(char &squareOne, char &squareTwo, char &squareThree, char &squareFour, char &squareFive, char &squareSix, char &squareSeven,
    char &squareEight, char &squareNine)
{


 cout << squareOne << "|" << squareTwo << "|" << squareThree << endl
  << "-+-+-"<< endl
  << squareFour << "|" << squareFive << "|" << squareSix << endl
  << "-+-+-"<< endl
  << squareSeven << "|" << squareEight << "|" << squareNine << endl;
 }
}

Answer 1

您可以让 showboard() 函数接受对 chars 的 3x3 数组的引用。奇怪的参数 char (&squares)[3][3] 表示“对名为 squares 的 3x3 chars 数组的引用”。

void showboard(char (&squares)[3][3]) 
{ 
    std::cout << squares[0][0] << "|" << squares[0][1] << "|"
         << squares[0][2] << "\n" << "-+-+-"<< "\n" 
         << squares[1][0] << "|" << squares[1][1] << "|"
         << squares[1][2] << "\n" << "-+-+-"<< "\n"
         << squares[2][0] << "|" << squares[2][1] << "|"
         << squares[2][2] << std::endl; 
} 

int main()
{
    char s[3][3] = { {'1', '2', '3'}, {'4', '5', '6'}, {'7', '8', '9'} };
    showboard(s);
}

或者，这里有一个使用 for 循环的实现:

void showboard(char (&squares)[3][3]) 
{ 
    for(int i = 0; i < 3; ++i)
    {
        for(int j = 0; j < 3; ++j)
        {
            std::cout << squares[i][j];
            if(j < 2) std::cout << "|";
        }
        std::cout << "\n";
        if(i < 2) std::cout << "-+-+-" << std::endl;;
    }
}