javascript - 如何在java脚本中的函数之后添加 $(document).ready(function(){})

Question

我想做的是我有如下代码:

$(document).ready(
  function(){
   var currentPage = window.location.pathname;
   $('#main-menu-list').find('a[href^="' + currentPage + '"]').closest('li').addClass('active');
  }  
)

现在我想添加此代码以添加其他代码并与其他代码一起使用。我需要在此代码之后添加此代码:

function () {
    /* If there are forms, make all the submit buttons in the page appear
       disabled and prevent them to be submitted again to avoid accidental
       double clicking. See Issue 980. */
    jQuery(function() {
        /* Delegate the function to document so it's likely to be the last event
           in the queue because of event bubbling. */
        jQuery(document).delegate("form", "submit", function (e) {
            var form = jQuery(this);
            if (form.hasClass("form_disabled")) {
                e.preventDefault();
                return false;
            }
            else {
                form
                  .addClass("form_disabled")
                  .find(":submit")
                    .addClass("disabled");
            }
            // Reactivate the forms and their buttons after 3 secs as a fallback.
            setTimeout(function () {
                form
                  .removeClass("form_disabled")
                  .find(":submit")
                    .removeClass("disabled");
            }, 3000);
        });
    });
}

我怎样才能完成这个任务。请帮我解决这个问题。

Answer 1

您可以在脚本中的任何位置创建document.ready()。您的所有代码不必都处于就绪状态。

您可以为函数创建实例变量并在需要的地方调用它:

$(document).ready(
  var myFunc = function(){
   var currentPage = window.location.pathname;
   //other code
  }  
  ...
 //and invoke it where you need
  myFunc();
)