swift - 如果变量是快速可选的，则展开变量？

Question

我正在尝试确定 Any 类型的变量是否是可选的，如果是，我需要将其解包。这可能吗？这段代码解释了我想要实现的目标。我知道 Optional 是通用的，我的编码方式行不通，想知道是否有解决方法

extension Serializable {
    public func serialize() -> [String: Any] {
        var result = [String: Any]()
        let mirror = Mirror(reflecting: self)

        for child in mirror.children {
            guard let label = child.label else { continue }

            if let optional = child.value as? Optional {
                if case Optional.some(let value) = optional {
                    result[label] = value
                }
            }
            else {
                result[label] = child.value
            }
        }

        return result
    }
}

Answer 1

我能够让它工作

extension Serializable {
    public func serialize() -> [String: Any] {
        var result = [String: Any]()
        let mirror = Mirror(reflecting: self)

        for child in mirror.children {
            guard let label = child.label else { continue }

            switch child.value {
            case let serializable as Serializable:
                result[label] = serializable.serialize()

            case let optional as Optional<Any>:
                if case .some(let value) = optional {
                    result[label] = value
                }

            default:
                result[label] = child.value
            }
        }

        return result
    }
}