C++ 需要帮助遍历卡片、定位对子和同花顺

Question

下面的程序假设正在寻找“对子”和“同花”。它迭代 10 次试验，包括 10,000 手牌，每手牌由 5 张牌组成。结果应该(当然现在不是)由 10 行组成，反射(reflect)每个试验的独特结果。我卡住了...提前致谢。

#include "card.h"
#include "deck.h"
#include "game1.h"
#include <iostream>
#include <time.h>
#include <stdlib.h>

using namespace std;


int main() {

int pair = 0;
int flush = 0;
int h;  //Hands
int c;  //Cards
int t;  //Trials

const int MAXTRIALS = 10;
const int MAXHANDS = 10000;
const int MAXCARDS = 5;
const int MAXSHUFFLE = 100;

Deck myDeck;
Card myCards[MAXCARDS];
myDeck.shuffle(MAXSHUFFLE);                         //How often would you shuffle?

srand((unsigned)time(NULL));                        //Randon initilizer

for (t = 0 ; t < MAXTRIALS; ++t)                    //Outermost loop for the Trials
{   

    for (h = 0; h < MAXHANDS; ++h)                  //InnerLoop for Hands
    {

        myCards[0] = myDeck.getCard();
        for (c = 1; c < MAXCARDS; ++c)              //InnerMost Loop for Cards
        {
            myCards[c] = myDeck.getCard();
            if (myCards[c].getValue() == myCards[0].getValue()) 
            {
                pair++;                 
            }

            if (myCards[c].getSuit() == myCards[0].getSuit())
            {
                flush++;                        
            }

            myDeck.addCard(myCards[c]);
            c++;

        }
        myDeck.shuffle(MAXSHUFFLE); 
        h++;
    }

    cout << "pairs: " << pair << "\tflushes: " << flush << endl;

}
cin.get();
}

Answer 1

如果我理解你的问题，“结果应该......由 10 行组成，反射(reflect)每次试验的独特结果”，问题很简单，你没有重置 对 和 flush 每次试验之间的计数器变量。像下面这样的“试用”for 循环开始的地方应该可以解决问题:

for (t = 0 ; t < MAXTRIALS; ++t) 
{
    pair = 0;
    flush = 0;

    // the remainder as is...