c++ - 2 条件的倍数不起作用(反问题)

Question

从技术上讲，我的这段代码是一个水壶模拟，但现在的问题是。当它到达 20.00 时，它的代码不起作用

#include<stdio.h>
#include<stdlib.h>
#include<cstdlib>
#include<time.h>


//Global Declaration  for waterTemperature
double nWaterTemp;

//Function for seconds :)
void wait ( int seconds ){
    clock_t endwait;
    endwait = clock () + seconds * CLOCKS_PER_SEC ;
    while (clock() < endwait) {
    }
}

//Function for increasing of hit of Kettle
void behaviourOn(){


    int counter = 1;

    while(nWaterTemp <=100.0){

        wait(1);
        printf("Ticking! %d\n",counter);
        if( counter%2 == 0&& nWaterTemp >=20.0 ){
                      nWaterTemp+=1.5/2.0;  
            printf("The water temp is %.2f\n",nWaterTemp); 

        }else if(counter%3==0){
            nWaterTemp+=2.0/3.0;
            printf("The water temp is %.2f\n",nWaterTemp);
        }else if(nWaterTemp == 20.0){
            system("cls");
            printf("THE KETTLE IS NOW ON!\n");
        }
            counter++;
    }
}

//Function for Envinronment
void environment(){
    int counter2 = 0;

    system("cls");
    printf("THE WATER IS NOW COOLING\n");
    while(nWaterTemp>=0){
        counter2++;
        wait(1);
        printf("Ticking! %d\n",counter2);

        if(counter2%3==0){
            nWaterTemp -=2.0/3.0;
            printf("The water temp is %.2f\n",nWaterTemp);
        }

    }
}

//main
int main(void){
    behaviourOn();
    environment();
    system("pause");    
}

你看，如果水温不高于 20.00，它只会每 2 秒增加一次，但在我的代码中，有时它的值每 1 秒变化一次，也有时每 2 秒变化一次更改...此代码中的错误是什么？

if( counter%2 == 0&& nWaterTemp >=20.0 ){//THe equation changes if it reach 20.00, and the heat increases every 2 seconds
                      nWaterTemp+=1.5/2.0;  
                      printf("The water temp is %.2f\n",nWaterTemp);

这就是让我感到困惑的部分，正如您在条件中看到的那样，如果应该每 2 秒增加一次温度值，但问题是它每 1 秒变化一次，然后有时每 1 秒变化一次，请帮忙

Answer 1

你应该这样写:

 if( nWaterTemp >=20.0 ) {
     if (counter%2 == 0) {
         nWaterTemp+=1.5/2.0;  
         printf("The water temp is %.2f\n",nWaterTemp); 
     }
 } else if ...

否则当counter % 2 != 0时，它会做错事