c++ - Loop 在获取输入之前完成一个循环，如何解决？

Question

while (1)
{
    cout << "Enter the Citizen ID number of the worker or Enter 0 to exit:" << endl;
    getline (cin, j);
    for (i=0; i<5; i++)
    {
        if (workers[i]->IDno == j) 
        {
            wFind = 1;
            cout << "Choose your option:" << endl;
            cout << "1- Display all details of the worker" << endl;
            cout << "2- Display number of the days worker delayed" << endl;
            cout << "3- Display number of the days worker missed" << endl;
            cin >> k;
            switch (k)
            {
            case 1:
                workers[i]->AWorker();
                break;
            case 2:
                cout << workers[i]->TotalDaysDelayed() << endl;
                break;
            case 3:
                cout << workers[i]->TotalDaysMissed() << endl;
                break;
            default:
                break;
            }
        }
        else
            wFind = 0;
    }

    if (wFind == 0)
        cout << "ERROR: No worker has the ID number that you typed!" << endl;
}

注意:wFind初始化为2。

当我执行这段代码时，我总是得到这样的输出:

Enter the Citizen ID number of the worker or Enter 0 to exit:
ERROR: No worker has the ID number that you typed!
Enter the Citizen ID number of the worker or Enter 0 to exit:

有趣的是，我的代码可以在获取字符串 j 的输入之前完成循环中的一个循环。这怎么可能？我该如何解决？

Answer 1

cin >> k; 不会吃掉换行符。您需要在它之后调用 std::getline 来使用换行符。

如果您在循环的第一次迭代中遇到问题，我会假设您在上面的代码也不会吃掉换行符。