swift - 快速向左滑动手势时出现无法识别的选择器错误

Question

我正在尝试创建一个简单的 swift left segue 到下一个 View Controller ，但是我收到了一个无法识别的选择器错误。这是代码失败:

   override func viewDidLoad() {
        super.viewDidLoad()

        //below creates the instances for swiping to change screens
        //only added right here because it's the main screen

          var swipeLeft : UISwipeGestureRecognizer = UISwipeGestureRecognizer(target: self, action: Selector("swipe:"))
        swipeLeft.direction = UISwipeGestureRecognizerDirection.Left

        self.view.addGestureRecognizer(swipeLeft)

        func swipe(Sender: UISwipeGestureRecognizer!) {
            print("swiped left")
            let vc = self.storyboard!.instantiateViewControllerWithIdentifier("OnDeck") as! OnDeck
            self.presentViewController(vc, animated: true, completion: nil)
        }
}

这是我遇到的错误:

2017-06-07 19:07:00.990 Test[65722:3911717] -[Test.GameView swipe:]: unrecognized selector sent to instance 0x7fc2d310f700
2017-06-07 19:07:01.000 Test[65722:3911717] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[Test.GameView swipe:]: unrecognized selector sent to instance 0x7fc2d310f700'

Answer 1

对于 Swift 3，选择器应如下所示:

#selector(swipe(Sender:))

您可以使用#selector 表示法进行编译时检查。

对于 Swift 2，选择器将是:

#selector(swipe(_:))