c++ - 如何使用 cin 测试空行

Question

下面是我用来将学生数据输入学生结构数组的函数的代码。我希望循环在我达到限制 (n) 时终止，这很好，或者，当为学生姓名键入空白行时，这就是我遇到的问题？有人有什么建议吗？我正在使用的当前方法不起作用('cin.getline(pa[i].fullname, SLEN - 1); 下面的 if 语句);')

int getinfo(student pa[], int n)
{
    cout << "\nPlease enter student details:\n\n";

    int i;
    for (i = 0; i < n; i++)
    {
        cout << "Student " << (i + 1) << ": \n";
        cout << "  > Full name: ";
        cin.getline(pa[i].fullname, SLEN - 1);
        if (pa[i].fullname == NULL)
            continue;
        cout << "  > Hobby: ";
        cin.getline(pa[i].hobby, SLEN - 1);
        cout << "  > OOP Level: ";
        cin >> pa[i].ooplevel;;
        cin.get();

        cout << endl;
    }

    cout << "--------------------------------------" << endl;

    return i;
}

Answer 1

更好地使用 string 和原子循环:

std::string name, hobby, oop;

std::cout << "Name: ";
if (!(std::getline(std::cin, name)) { break; }

std::cout << "Hobby: ";
if (!(std::getline(std::cin, hobby)) { break; }

std::cout << "OOP: ";
if (!(std::getline(std::cin, oop)) { break; }

// if we got here, everything succeeded.
pa[i].name = name; pa[i].hobby = hobby; pa[i].oop = oop;

// or better, pass a `std::vector<student> &`:
pa.push_back(student(name, hobby, oop));