gpt4 book ai didi

javascript - 按需 infovis 超树节点

转载 作者:行者123 更新时间:2023-11-28 08:05:26 26 4
gpt4 key购买 nike

我对使用 Javascript Infovis Toolkit 还很陌生,但我想做的是创建一个 super 树,其中五个初始节点连接到中间。然后,当用户单击每个子节点时,会出现连接到该子节点的新节点(其中 6 个)。但我不知 Prop 体该怎么做。这是我的树代码:

            //now puts in tree and detailer
var infovis = document.getElementById('infovis');
var w = infovis.offsetWidth, h = infovis.offsetHeight;

var ht = new $jit.Hypertree({
//id of the visualization container
injectInto: 'infovis',
//By setting overridable=true,
//Node and Edge global properties can be
//overriden for each node/edge.
Node: {
overridable: true,
'transform': true,
type: 'circle',
},

Edge: {
overridable: true,
lineWidth: 5,
color: "lightgrey"
},
//calculate nodes offset
offset: 0.2,
//Change the animation transition type
transition: $jit.Trans.Back.easeOut,
//animation duration (in milliseconds)
duration: 1000,

//Attach event handlers on label creation.
onCreateLabel: function (domElement, node) {
domElement.innerHTML = node.name;
domElement.style.cursor = "pointer";
domElement.onclick = function () {
ht.onClick(node.id, {
hideLabels: false,
onComplete: function () {
ht.controller.onComplete();
}
});
};
},
//This method is called when moving/placing a label.
//You can add some positioning offsets to the labels here.
onPlaceLabel: function (domElement, node) {
var width = domElement.offsetWidth;
var intX = parseInt(domElement.style.left);
intX -= width / 2;
domElement.style.left = intX + 'px';
},

onBeforeCompute: function (node) {
//fades info out
$("#inner-details").fadeOut(500);
},

onComplete: function () {
//Make the relations list shown in the right column.
var node = ht.graph.getClosestNodeToOrigin("current");
var html = "<h2>" + node.name + "</h2>";
html += "<p>" + node.data.Explanation + "</p>"
$jit.id('inner-details').innerHTML = html;

//fades info out
$("#inner-details").fadeIn(500);


}
});



//load JSON graph.
ht.loadJSON(json, 2);
//compute positions and plot
ht.refresh();

最佳答案

Get data of first level only when user click on node then ajax call
get that node childrens data.
var lastClickedNode = '';
onCreateLabel: function(domElement, node) {
domElement.innerHTML = node.name;
$jit.util.addEvent(domElement, 'click', function() {
if (lastClickedNode == node) {
return;
}
lastClickedNode = node;
if (node.children.length == 0 && node.hasFurtherData) {
$.ajax({
url: "apiurl/" + node.id,
method: "GET",
crossDomain: true,
dataType: "json",
contentType: 'application/json',
beforeSend: function(xhr) {
xhr.setRequestHeader('Access-Control-Allow-origin', '*');
},
header: {
"Content-Type": "application/json",
"Accept": "text/javascript; charset=utf-8"
},
success: function(data) {
ht.op.sum(data, {
type: 'replot',
hideLabels: true,
transition: $jit.Trans.Back.easeInOut
});
ht.refresh();
ht.onClick(node.id);
}
});
} else {
ht.onClick(node.id);
}
});
}

关于javascript - 按需 infovis 超树节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24835417/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com