c++ - 在此字符串操作代码中出现 out_of_range 错误

Question

嗨，我正在点击 std::out_of_range: basic_string::substr在下面的代码中。一直在努力修复它，但无法完成。

std::string orig_str = "1-1,2-3,4-4,56-75,77-77";
size_t number_digits;
for (size_t i = 0; i < orig_str.size(); ++i)
{
    number_digits = orig_str.find_first_of(",", i) - i - 1;
    if(orig_str.find("-", i) != std::string::npos)
    if (orig_str.substr(i - number_digits, i - 1) == orig_str.substr(i + 1, i + number_digits))
    orig_str.erase(i-number_digits, number_digits + 1);            
}

基本上这段代码是通过操作字符串来移除一些范围预期行为是:输入字符串: "0-0,2-7,88-88"输出字符串: "0,2-7,88"

Answer 1

AJ，这是我们在聊天中讨论的伪代码:

input_string = "1-1,2-3,4-4,56-75,77-77"
output_string = ""
while (input_string is not empty)
    sub = input_string.substr(up to first comma)
    input_string = input_string.substr(after first comma)
    if (sub.substr(up to dash) == sub.substr(after dash))
        output_string += sub.substr(up to dash)
    else
        output_string += sub
    if (input_string is not empty)
        output_string += ","