c++ - long * tempArray[10]; 是什么意思？做？

Question

能否请您解释一下这段 C++ 代码的作用:

int main()
{
    long * tempArray[10];
}

感谢您的帮助!

Answer 1

那段特定的代码根本没有任何作用。如果您编译该程序，它将终止并向托管环境报告它已成功终止，仅此而已。

long * tempArray[10]; 声明了一个名为 tempArray 的变量，其类型为 array 10 of pointer to long，这意味着tempArray 能够容纳 10 个 long * 对象。

出于演示目的:

// declare some long integers
long myLong = 100;
long anotherLong = 400;
long thirdLong = 2100;

// declare array 3 of pointer to long
long *tempArray[3];

// remember that arrays in C and C++ are 0-based, meaning index 0
// refers to the first object in an array. Here we are using the `&'
// operator to obtain a long pointer to each of the longs we declared
// and storing these long pointers in our array.
tempArray[0] = &myLong;
tempArray[1] = &anotherLong;
tempArray[2] = &thirdLong;