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javascript - 需要关于ajax成功功能的建议

转载 作者:行者123 更新时间:2023-11-28 08:00:08 25 4
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我有一个小问题 - 我正在进行 ajax 查询以将数据传输到另一个 php 文件,一旦查询成功,我需要加载一个脚本。

$.ajax({
type: 'POST',
url: 'promote.php',
data: { country:country },
success: function() {
//What to do here?
}
});

脚本是:

<script type="text/javascript">
var var1 = "d1dtGWhrOaxxUVCy%2FNjJwkpd9lCj%2FGijAGXS5d7LYPU%3D";
var var2 = "jn9drdklwlr5hjYc2eHTCaXRjdpHDqhaqL5LXpsyc54%3D";
var var3 = "E770DuKV8GKaHhaZO%2B%2F9sPzUI9mAUFVRrxRTH75pHvA%3D";
var var4 = "LhWNAMH8CgveH%2FqRHKxqg8ebEVZKTX4pQw3pp5wTRl8%3D";
var network = "xxxxxxx";
</script>
<script type="text/javascript" src="http://xxxxxxx/js/xx.js"></script>

那么,当ajax查询成功时,我该如何加载这个脚本,有什么建议吗?我需要在此文件中执行此操作,请不要建议将脚本放入其他文件中并从中加载。这可能吗?

最佳答案

$.ajax({
type: 'POST',
url: 'promote.php',
data: { country:country },
success: function() {

var script='<script type="text/javascript">';
script+='var var1 = "d1dtGWhrOaxxUVCy%2FNjJwkpd9lCj%2FGijAGXS5d7LYPU%3D";';
script+='var var2 = "jn9drdklwlr5hjYc2eHTCaXRjdpHDqhaqL5LXpsyc54%3D"';
script+='var var3 = "E770DuKV8GKaHhaZO%2B%2F9sPzUI9mAUFVRrxRTH75pHvA%3D"';
script+='var var4 = "LhWNAMH8CgveH%2FqRHKxqg8ebEVZKTX4pQw3pp5wTRl8%3D"';
script+='var network = "xxxxxxx"';
script+='</script>';
script+='<script type="text/javascript" src="http://xxxxxxx/js/xx.js"></script>';
$("head").append(script);
}
});

关于javascript - 需要关于ajax成功功能的建议,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25547040/

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