javascript - Ajax Jquery 和 php : How to control feedback?

Question

假设您通过 ajax 发送数据。服务器将对其进行处理 (PHP) 并发送反馈，您可以使用 Complete: function(data) {//WRITE HTML TO DIV $('#somehin').html(data) } 获取反馈问题是:有没有办法在将数据传递给 html 元素之前修改数据(编辑、删除)？

这是一个简单的例子来说明我的意思:

//php side
echo 'Invalid email';
echo 'Enter your username';
echo 'fine';
echo 1;
echo 2;


// Jquery and Ajax
$.ajax({
type: 'POST',
url: 'render.php',
data:values,
complete: function(data) {
$('#something').html(data) /* all those messages in php will be printed 
into #something including the numbers. how to delete or edit those numbers 
from appearing in #something? */
}
});

Answer 1

尝试删除这样的数字，

complete:function(data){
   data=data.replace(/\d+/,''); // Regular expression without quotation marks.
   // or you can replace the something text like
   // $('#something').text(function(){
   //     return this.innerText.replace(/\d+/,'');
   // });
   alert(data);
}