c++ - 模板初始化构造函数错误

Question

嘿，我不知道如何让我的模板标题工作。我必须让我的 init 构造函数接收一个数组并将其反转。因此，例如，如果我有 [1,2,3,4]，它会在 [4,3,2,1] 中接受它

这是我的模板类:

#pragma once
#include <iostream>

using namespace std;

template<typename DATA_TYPE>
class Reverser
{
private:
    // Not sure to make this DATA_TYPE* or just DATA_TYPE
    DATA_TYPE Data;
public:
     // Init constructor
     Reverser(const DATA_TYPE& input, const int & size)
    {
        // This is where I'm getting my error saying it's a conversion error (int* = int), not sure
        // What to make Data then in the private section. 
        Data = new DATA_TYPE[size];
        for(int i=size-1; i>=0; i--)
            Data[(size-1)-i] = input[i];
    }

    DATA_TYPE GetReverse(){
        return Data;
    }

    ~Reverser(){
        delete[] Data;
    }

};

是的，如果你能告诉我我做错了什么，那就太好了。

Answer 1

那是因为当您将数组传递给函数时，它会转换为指针。您必须使用 DATA_TYPE 作为指针:

template<typename DATA_TYPE>
class Reverser
{
private:
    // Not sure to make this DATA_TYPE* or just DATA_TYPE
    DATA_TYPE* Data; //pointer
public:
     // Init constructor
     Reverser(const DATA_TYPE* input, const int & size) //pointer
    {
        // This is where I'm getting my error saying it's a conversion error (int* = int), not sure
        // What to make Data then in the private section. 
        Data = new DATA_TYPE[size];
        for(int i=size-1; i>=0; i--)
            Data[(size-1)-i] = input[i];
    }

    DATA_TYPE* GetReverse(){ //Returns Pointer
        return Data;
    }

    ~Reverser(){
        delete[] Data;
    }
};