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javascript - 未捕获的类型错误 : Cannot set property 'innerHTML' of null in javascript

转载 作者:行者123 更新时间:2023-11-28 07:41:04 24 4
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<html>
<head>
<title>Testing</title>


</head>
<body>
<script type="text/javascript">
var target_date = new Date('Jan 04 2022 20:47:00').getTime();
var localMinDiff = new Date().getTimezoneOffset() * 60000;
target_date = target_date - localMinDiff;
var days, hours, minutes, seconds;
var countdown = document.getElementById('timeremaining');
var countdownTimer = setInterval(function () {
var current_date = new Date().getTime();
var seconds_left = (target_date - current_date) / 1000;

days = parseInt(seconds_left / 86400);
seconds_left = seconds_left % 86400;

hours = parseInt(seconds_left / 3600);
seconds_left = seconds_left % 3600;
minutes = parseInt(seconds_left / 60);
seconds = parseInt(seconds_left % 60);

if(days <= 0 && hours <= 0 && minutes <= 0 && seconds <= 0 )
{
countdown.innerHTML = 'time ended';
clearInterval(countdownTimer);
}
else
{
if(days>0)
{
days= days+'d,';
}
else
{
days='';
}


countdown.innerHTML ='( ' + days + checkTime(hours) + ':'+ checkTime(minutes) + ':' + checkTime(seconds) +' remaining)';
}
}, 1000);

function checkTime(i) {
if (i < 10) {i = '0' + i};
return i;
}
</script>
time remaining =

<div id="timeremaining"></div>
</body>
</html>

我正在尝试运行此反向计时器,但它确实显示任何内容。 当我记录它时,我收到一条错误消息。 我还检查了它增加的计时器持续时间,但仍然收到错误。当我提醒它时,我得到了准确的倒计时。

最佳答案

该脚本需要在元素加载后运行。问题是您正在对尚不存在的元素调用innerHTML。

关于javascript - 未捕获的类型错误 : Cannot set property 'innerHTML' of null in javascript,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28012667/

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