c++ - 将数组推送到 C++ 中的函数？

Question

        {
            int a[3];
            mainClassStack.pushNumber(a[1,2,3]);
            break;
        }

void stack_class::pushNumber(int numberFunc)
{
    if(head==NULL)
    {
        head = new stack_struct;
        head->number = numberFunc;
        head->next_number = NULL;
        tailPointer=head;
    }
    else
    {
        pointerFunc = new stack_struct;
        pointerFunc->number=numberFunc;
        pointerFunc->next_number=NULL;
        head->next_number=pointerFunc;
        head=pointerFunc;
    }
}


void stack_class::pushNumber(char charFunc)
{

    int a=0;
    a=charFunc;
    if(head==NULL)
    {
        head = new stack_struct;
        head->number = a;
        head->next_number = NULL;
        tailPointer=head;
    }
    else
    {
        pointerFunc = new stack_struct;
        pointerFunc->number=a;
        pointerFunc->next_number=NULL;
        head->next_number=pointerFunc;
        head=pointerFunc;
    }

}


void stack_class::pushNumber(int arrayFunc[3])
{
    if(head==NULL)
    {
        for(int i=0;i<3;i++)
        {
            head = new stack_struct;
            head->number = arrayFunc[i];
            head->next_number = NULL;
            tailPointer=head;
        }
    }
    else
    {
        for(int i=0;i<3;i++)
        {
            pointerFunc = new stack_struct;
            pointerFunc->number=arrayFunc[i];
            pointerFunc->next_number=NULL;
            head->next_number=pointerFunc;
            head=pointerFunc;
        }
    }
}

我正在重载函数并将数组推送到适当的函数中，该函数稍后会将数组中的值添加到动态链表中。到目前为止我已经写了这个，但是当我尝试打印链接列表时，它显示垃圾。我在这里做错了什么？

Answer 1

这对您来说更有意义吗？

void Foo(int arg[])
{
  printf("%i\n", arg[0]);
  printf("%i\n", arg[1]);
  printf("%i\n", arg[2]);
}

int main()
{
  int a[3] = {1,2,3};
  Foo(a);
  return 0;
}

输出是:

1
2
3