c++ - 在 do/while 循环中跳过 Cin 输入

Question

cin >> subchoice;
        switch(subchoice)
        {
        case 1:
            gold = gold - 5;
            cout << "Now you only have " << gold << " gold.\n";
            cout << "blah blah";
            health = 100;
            break;
        case 2:
            cout << "blah blah"
                    << "1 - Head Back in and Buy a Bed\n"
                    << "2 - Find a Clothier Shop\n"
                    << "3 - Find a Blacksmith's\n";
            cin >> subsubchoice;
            switch(subsubchoice)
            {
            case 1:
                gold = gold - 5;
                cout << "Now you only have " << gold << " gold.\n";
                cout << "blah blah"
                health = 100;
                break;
            case 2:
                menuchoice = subsubchoice;
                break;
            case 3:
                menuchoice = subsubchoice;
                break;
            }
        }

    break;
    case 2:

    }




} while (!boolchoice);

嘿，我这里有这段代码。每当我运行它时，它总是会跳过 subsubchoice 的 cin 输入。它应该做的是获取该输入，然后让您进入旅馆或将该选择应用于 menuchoice 并在 do-while 循环的开头重新启动您。我不知道为什么它会跳过输入然后关闭程序。感谢您的帮助。

Answer 1

也许你需要在 cin >> subsubchoice; 之前添加 cin.ignore()