C++ 显示文本文件... ("Echo"文本文件)

Question

所以我真的一直在试图找出程序中阻止我显示程序文本的错误..

#include <iostream>
#include <iomanip>
#include <fstream>
#include <sstream>
#include <string>
#include <stdio.h>
using namespace std;

int main ()
{
ifstream infile;
ofstream offile;

char text[1024];
cout <<"Please enter the name of the file: \n";
cin >> text;

infile.open(text);

string scores; // this lines...

getline(infile, scores, '\0'); // is what I'm using...

cout << scores << endl; // to display the file...

---

string name1;
int name2;
string name3;
int name4;
infile >> name1;
infile >> name2;
infile >> name3;
infile >> name4;

cout << "these two individual with their age add are" << name2 + name4 <<endl;

// 23 + 27

//the result I get is a bunch of numbers...

return 0;

}

有没有更清晰或更简单的方法可以用来显示文件？

互联网上的所有方法都难以理解或跟踪，因为文件在循环中打开..

我想要一个你输入文件名并显示文件的程序该文件将包含以下内容...

jack 23 
smith 27

我还需要从文件中获取数据，现在我正在使用上面的代码从文件中获取该信息...

Answer 1

循环可能是您能做的最好的事情。所以如果你知道格式你可以简单地这样做

#include <iostream>
#include <fstream>
using namespace std;
int printParsedFile(string fileName) {  // declaration of a function that reads from file passed as argument
    fstream f;     // file stream
    f.open(fileName.c_str(), ios_base::in);     // open file for reading
    if (f.good()) {     // check if the file can be read
        string tmp;     // temp variable we will use for getting chunked data
        while(!f.eof()) {     // read data until the end of file is reached
            f >> tmp;     // get first chunk of data
            cout << tmp << "\t";     // and print it to the console
            f >> tmp;     // get another chunk
            cout << tmp << endl;     // and print it as well

    } else {
        return -1; // failed to open the file
    }
    return 0; // file opened and read successfully
}

然后你可以在你的 main() 函数中调用这个函数来读取和显示作为参数传递的文件

int main(int argc, char** argv) {
     string file;
     cout << "enter name of the file to read from: "
     cin >> file;
     printParsedFile(file);
     return 0;
}