c++ - 在消息中显示每个字符的十六进制？

Question

想在消息中显示每个字符的十六进制(如果可能的话，简单的方法，我知道我可以遍历字符并执行此操作):

typedef struct{
    double dTime;
    char cMessage[11];
} typeCanMessage;

typeCanMessage cmMessage1 = {4.5, {0xd2, 0xf1, 0xe0, 0xf1, 0xf1, 0xf1, 0xf1, 0x23, 0x23, 0x23, 0x23}};

QMessageBox *msgBox = new QMessageBox(0);
msgBox->setGeometry(QRect(QPoint(200,200),QSize(400,400)));
msgBox->setInformativeText(QString::number(cmMessage1.dTime, 'f', 8) + "  "
     + QString::number(cmMessage1.cMessage, 'x')); // <-- something like this perhaps
msgBox->exec();

错误:“调用重载的‘number(char[11], char)’不明确”

修改:

sprintf(cM, "%x", &cmMessage1.cMessage);

QMessageBox *msgBox = new QMessageBox(0);
msgBox->setGeometry(QRect(QPoint(200,200),QSize(400,400)));
msgBox->setInformativeText(QString::number(cmMessage1.dTime, 'f', 8) + "  "
     + (QString)cM); // <-- something like this perhaps
msgBox->exec();

结果:bfb123d8//错误

---

我想避免执行以下操作(循环或不循环):

 sprintf(cM, "%X%X%X%X%X%X%X%X%X%X%X", cmMessage1.cMessage[0],
                            cmMessage1.cMessage[1],
                            cmMessage1.cMessage[2],
                            cmMessage1.cMessage[3],
                            cmMessage1.cMessage[4],
                            cmMessage1.cMessage[5],
                            cmMessage1.cMessage[6],
                            cmMessage1.cMessage[7],
                            cmMessage1.cMessage[8],
                            cmMessage1.cMessage[9],
                            cmMessage1.cMessage[10]);

循环:

for(int i = 0; i < 11; i++){
    sprintf(cM + 2 * i, "%X", cmMessage1.cMessage[i]);

}

Answer 1

number 函数只是格式化一个数字。如果你想格式化数组中的每个数字，你需要一个循环，按照

auto text = QString::number(cmMessage1.dTime, 'f', 8) + "  ";
for (unsigned c : cmMessage1.cMessage) {
    text += QString::number(c,16);
}
msgBox->setInformativeText(text);

(您还应该使用 unsigned char，而不是 char，来存储 8 位无符号值)。