javascript - 单击时隐藏弹出窗口

Question

我使用下面的脚本创建一个弹出窗口。当用户点击弹出窗口时如何隐藏弹出窗口？

if (document.cookie.indexOf('_visited=1') == -1) {
    var delay_popup = 1000;
    setTimeout("document.getElementById('parent_popup').style.display='block'", delay_popup);
    var date = new Date;
    date.setDate( date.getDate() + 1 ); // текущая дата + 1 день
    document.cookie = '_visited=1; path=/; expires=' + date.toUTCString();
}

Answer 1

您可以像这样添加 onclick 事件:

if (document.cookie.indexOf('_visited=1') == -1) {
    var delay_popup = 1000;
    setTimeout("document.getElementById('parent_popup').style.display='block'", delay_popup);
    var date = new Date;
    date.setDate(date.getDate() + 1); // текущая дата + 1 день
    document.cookie = '_visited=1; path=/; expires=' + date.toUTCString();

    document.getElementById('parent_popup').onclick = function() {
        this.style.display = 'none';
    }
}