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c++ - 类中的递归函数或竞争条件?

转载 作者:行者123 更新时间:2023-11-28 07:27:30 25 4
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在下面的代码中,私有(private)函数handle_read_content 使用asio::async_read,它依赖于handle_read_content。这会调用递归行为或创建竞争条件吗?

class client
{
public:
//constrcutor, io_service, server name? path?

client(asio::io_service& io_service,
const std::string& server, const std::string& path)
: resolver_(io_service),
socket_(io_service)
{
//form request, connection close header server close the socket
//std:ostream reuest_stream


// Form the request. We specify the "Connection: close" header so that the
// server will close the socket after transmitting the response. This will
// allow us to treat all data up until the EOF as the content.
std::ostream request_stream(&request_);
request_stream << "GET " << path << " HTTP/1.0\r\n";
request_stream << "Host: " << server << "\r\n";
request_stream << "Accept: */*\r\n";
request_stream << "Connection: close\r\n\r\n";

// Start an asynchronous resolve to translate the server and service names
// into a list of endpoints.
//tcp:resolver:query

tcp::resolver::query query(server, "http");

resolver_.async_resolve(query,
boost::bind(&client::handle_resolve, this,
asio::placeholders::error,
asio::placeholders::iterator));
}

private:


void handle_read_content(const asio::error_code& err)
{
if (!err)
{
// Write all of the data that has been read so far.
std::cout << &response_;

// Continue reading remaining data until EOF.
asio::async_read(socket_, response_,
asio::transfer_at_least(1),
boost::bind(&client::handle_read_content, this,
asio::placeholders::error));
}
else if (err != asio::error::eof)
{
std::cout << "Error: " << err << "\n";
}
}

tcp::resolver resolver_;
tcp::socket socket_;
asio::streambuf request_;
asio::streambuf response_;
};

最佳答案

这不是递归的,handle_read_content 是一个回调函数,将在 async_read 操作完成时调用。

http://www.boost.org/doc/libs/1_54_0/doc/html/boost_asio/reference/async_read/overload1.html

这是 async_read 应该工作的方式,这是它正在做的事情:

  1. 阅读一些数据
  2. boost 调用在读取操作完成时调用 handle_read_content
  3. 这会调用一个新的 async_read... 并且该过程会再次开始...直到发生错误。

关于c++ - 类中的递归函数或竞争条件?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18477990/

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