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c++读取csv文件并操作数据然后打印错误

转载 作者:行者123 更新时间:2023-11-28 07:25:01 26 4
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这是我的问题的延续:c++ reading in text file into vector<vector> then writing to vector or array depending on first word in internal vector .我正在读取一个文件并使用节点坐标的值来计算单元中心,并希望使用标题打印单元中心文件:ID、X、Y、Z,其中 Z 全部为 0。

到目前为止的代码:

#include <algorithm>
#include <fstream>
#include <iostream>
#include <iterator>
#include <sstream>
#include <string>
#include <vector>
#include <cstdlib>

std::vector<double> GetValues(const std::vector<std::string>& src, int start, int end)
{
std::vector<double> ret;
for(int i = start; i <= end; ++i)
{
ret.push_back(std::strtod(src[i].c_str(), nullptr));
}
return ret;
}

std::vector<double> polycentre(const std::vector<double>& x,const std::vector<double>& y,int ID)
{
std::vector<double> C(3, 0);
std::vector<double> x1(x.size(),0);
std::vector<double> y1(y.size(),0);
int sizx = x.size();
int sizy = y.size();
if(sizy != sizx)
{
std::cerr << "polycentre inputs not equal length";
}
double x0 = x[0];
double y0 = y[0];
for(int aa = 1; aa < sizx; ++aa)
{
if(x[aa] < x0){x0 = x[aa];}
if(y[aa] < y0){y0 = y[aa];}
}
double A = 0.0;
double B = 0.0;
for(int aa = 0; aa < sizx; ++aa)
{
x1[aa] = x[aa] - x0;
y1[aa] = y[aa] - x0;
if(aa != sizx-1)
{
A = A + (x1[aa]*y1[aa+1] - x1[aa+1]*y1[aa]);
B = B + ((x1[aa]+x1[aa+1])*(x1[aa]*y1[aa-1]-x1[aa-1]*y1[aa]));
}
else if(aa == sizx-1)
{
A = A + (x1[aa] - y1[aa]);
B = B + ((x1[aa]+1)*(x1[aa]*1-1*y1[aa]));
}
}
A = A*0.5;
C[0] = ID;
C[1] = ((1/6/A)*B)+x0;
C[2] = ((1/6/A)*B)+y0;
return C;
}

void PrintValues(const std::string& title, std::vector<std::vector<double>>& v)
{
std::cout << title << std::endl;
for(size_t line = 0; line < v.size(); ++line)
{
for(size_t val = 0; val < v[line].size(); ++val)
{
std::cout << v[line][val] << " ";
}
std::cout << std::endl;
}
std::cout << std::endl;
}

int main()
{
std::vector<std::vector<std::string>> values;
std::ifstream fin("example.2dm");
for (std::string line; std::getline(fin, line); )
{
std::istringstream in(line);
values.push_back(
std::vector<std::string>(std::istream_iterator<std::string>(in),
std::istream_iterator<std::string>()));
}

std::vector<std::vector<double>> cells;
std::vector<std::vector<double>> nodes;
for (size_t i = 0; i < values.size(); ++i)
{
if(values[i][0] == "E3T")
{
cells.push_back(GetValues(values[i], 1, 5));
}
else if(values[i][0] == "E4Q")
{
cells.push_back(GetValues(values[i], 1, 6));
}
else if(values[i][0] == "ND")
{
nodes.push_back(GetValues(values[i], 1, 4));
}
}
std::vector<std::vector<double>> cell_centres;
for (size_t aa = 0; aa < cells.size(); ++aa)
{
if(cells[aa].size() == 4)
{
std::vector<double> xs = {nodes[cells[aa][1]][1], nodes[cells[aa][2]][1], nodes[cells[aa][3]][1]};
std::vector<double> ys = {nodes[cells[aa][1]][2], nodes[cells[aa][2]][2], nodes[cells[aa][3]][2]};
cell_centres.push_back(polycentre(xs,ys,aa));
}
}

PrintValues("Cell Centres", cell_centres);
PrintValues("Cells", cells);
PrintValues("Nodes", nodes);

return 0;
}

当我运行该程序时,我没有得到关于细胞中心的任何输出:

$ ./a.exe
Cell Centres

Cells
1 19 20 14 16 2
2 17 16 15 23 2
3 22 15 14 21 2
4 4 3 21 20 1
5 6 20 19 7 1
6 18 17 10 9 1
7 17 23 12 11 1
8 7 19 18 8 1
9 22 1 13 23 1
10 14 20 21 2
11 21 2 22 1
12 21 3 2 1
13 22 2 1 1
14 5 20 6 1
15 20 5 4 1
16 16 14 15 2
17 23 13 12 1
18 22 23 15 2
19 17 11 10 1
20 17 18 16 2
21 8 18 9 1
22 18 19 16 2

Nodes
1 -325.811 77.0286 0
2 -324.209 76.0395 0
3 -323.012 74.4784 0
4 -322.754 72.5327 0
5 -323.617 70.8079 0
6 -325.162 69.8134 0
7 -327.129 69.876 0
8 -329.096 69.9385 0
9 -330.301 71.4668 0
10 -330.787 73.3242 0
11 -330.836 75.2916 0
12 -329.587 76.5401 0
13 -327.743 77.227 0
14 -326.109 73.2068 0
15 -327.041 74.207 0
16 -327.35 73.1717 0
17 -329.154 74.0024 0
18 -328.659 71.9967 0
19 -326.846 71.4063 0
20 -325 72.0535 0
21 -324.701 73.9639 0
22 -326.168 75.3361 0
23 -328.06 75.4195 0

谁能告诉我哪里出错了??

顺便说一下,MATLAB 代码是:

函数cell_centres(infil,outfil)

% read 2DM file
MESH = RD2DM(infil);

% get cell centres
if (isfield(MESH,'E3T'))
ne3 = length(MESH.E3T);
else
ne3 = 0;
end
if (isfield(MESH,'E4Q'))
ne4 = length(MESH.E4Q);
else
ne4 = 0;
end

ne = ne3 + ne4;
ctrd = zeros(ne,2);
id = zeros(ne,1);
z = zeros(ne,1);
k = 1;

if (isfield(MESH,'E3T'))
for i = 1:length(MESH.E3T)
pts = MESH.E3T(i,2:4);
x = MESH.ND(pts,2);
y = MESH.ND(pts,3);
z(k) = mean(MESH.ND(pts,4));
ctrd(k,:) = polycentre(x,y);
id(k) = MESH.E3T(i,1);
k = k+1;
end
end

if (isfield(MESH,'E4Q'))
for i = 1:length(MESH.E4Q)
pts = MESH.E4Q(i,2:5);
x = MESH.ND(pts,2);
y = MESH.ND(pts,3);
z(k) = mean(MESH.ND(pts,4));
ctrd(k,:) = polycentre(x,y);
id(k) = MESH.E4Q(i,1);
k = k+1;
end
end

% order cell ids
[id i] = sort(id,'ascend');
ctrd = ctrd(i,:);
z = z(i);

% write .csv file
fid = fopen(outfil,'w');
fprintf(fid,'%s\n','ID,X,Y,Z');

for aa = 1:ne
fprintf(fid,'%i,%.7f,%.7f,%.7f\n',id(aa),ctrd(aa,1),ctrd(aa,2),z(aa));
end

fclose(fid);

display('done & done :-)')

干杯

最佳答案

删除下面两行的&

    std::vector<double> xs = {&nodes[cells[aa][1]][1], &nodes[cells[aa][2]][1], &nodes[cells[aa][3]][1]};
std::vector<double> ys = {&nodes[cells[aa][1]][2], &nodes[cells[aa][2]][2], &nodes[cells[aa][3]][2]};

您需要 double 值而不是 integers(& 运算符获取整数类型的地址)。初始化列表不会为您进行隐式转换。

关于c++读取csv文件并操作数据然后打印错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18907620/

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