C++ 自定义用户定义主要？

Question

我对提供给我们的这段代码感到非常困惑:

class KeyedWord
{
public:
    KeyedWord(char* word); // TO BE IMPLEMENTED
    char* getWord(); // TO BE IMPLEMENTED
    char* getKey();  // TO BE IMPLEMENTED
    ~KeyedWord();
private:
    char * _word;
    char* _key;
};
void main(int argumentCount, char** arguments)
{
    if (argumentCount <= 1) 
    {
        std::cout << "No file name given as argument" << std::endl;
    }
    else 
    {
}

我很困惑，因为:

如果 main 是程序的起源，我应该如何为 main 提供重载？

此外，当我尝试实现上述功能之一时，我收到一条错误消息，告诉我存在定义错误。这就是我正在尝试的:

void KeyedWord::getWord()
{

    return;
}

Answer 1

您不能重载 main 函数。

来自标准:

3.6.1 Main function [basic.start.main]

2/ An implementation shall not predefine the main function. This function shall not be overloaded. It shall have a return type of type int, but otherwise its type is implementation-defined. All implementations shall allow both:

• a function of () returning int and
• a function of (int, pointer to pointer to char) returning int

---

你也声明

 class KeyedWord
{
public:
    // ...
    char* getWord(); // TO BE IMPLEMENTED

    // ...
};

然后您将方法定义为

   void KeyedWord::getWord() { ... }
// ^^^^

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